•Removing a node with 2
children
–However, there is a
special case
–If the right child has
no left children, then the right child becomes
the inorder successor
•Should this be done
recursively or iteratively?
–it is common to “find
the node who’s data matches the data to be
removed” using recursion
–but, finding the
inorder successor should be done iteratively,
because we simply “loop” until the left pointer
is null.