Selection Sort
Remember that means for the first time
around there would be N-1 comparisons.
The next time around there would be N-2
comparisons (because we can exclude comparing
the previously found largest! Its already in the
correct spot!).
The third time around there would be N-3
comparisons.
So...the number of comparisons would be:
       (N-1)+(N-2)+...+ 1 = N*(N-1)/2