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In
addition, the algorithm moves data at
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most
the same number of times.
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So,
including both comparisons and
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exchanges,
we get N(N-1) = N*N - N
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This can be summarized as a O(N2)
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algorithm
in the worst case.
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We
should keep in mind that this means as our
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list
grows larger the performance will be
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dramatically
reduced.
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