Insertion Sort
With the first pass,
we make 1 comparison.
With the second pass, in the worst case we must make 2
comparisons.
With the third pass, in the worst case we must make 3
comparisons.
With the N-1 pass, in the worst case we must make N-1
comparisons.
In worst case: 1 + 2 + 3 + ... + (N-1)
which is: N*(N-1)/2     O(N2)