CS202
6- ‹#›
[] Operator
string &
list::operator [] (int index) const {
node * current = head;
for (int i=0; i< index &&
current; i++)
current = current->next;
if (!current) {
//consider what other alternatives there
are
string * temp = new string; //just in
case
return *temp;
}
return current->obj;
}
n
nNotice how we must consider each special case (such as
an index that goes beyond
the number of nodes provided in the
linked list