CS202
6- ‹#›
+= Operators
list & list::operator
+= (const list & l2) {
//why wouldn’t we program this way?
*this = *this + l2;
return *this;
}
n
Or, would it be better to
do the following?
n
list & list::operator
+= (const list & l2) {
if (!head) *this =
l2; //think about this...
else {
node * dest = tail;
node * source = l2.head;
while (source) {
dest->next = new node;
dest = dest->next;
dest->obj = source->obj;
source = source->next;
}
dest->next = NULL; tail = dest; //ptr =
temp.head; yes?
} return *this;
}
n