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| • |
Type
conversions will not help when operators are
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members
-- because a member is required to have the first
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operand
as an object of the class; if it converted to some
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other
type, the member function will not be found as a
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possible
candidate function and a compile error will result
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or
the wrong operator will be used (such as the built-in
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operators).
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Also,
when user defined conversions to built-in types have
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been
specified, the predefined operators may end up being
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used
even when we use an operator with a user defined
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type
for which an overloaded operator exists! Overloaded
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operators
are only invoked if at least one of those operands
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is a
user defined type.
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